cf.dtlt

cf.dtlt(*args, **kwargs)

Return a comparison object for a date-time object being earlier than a date and time.

cf.dtlt(*args, **kwargs) is equivalent to cf.lt(cf.dt(*args, **kwargs)).

Parameters :

args, kwargs :

Positional and keyword arguments for defining a date-time. See cf.dt for details.

Returns :

out : cf.Comparison

The comparison object.

See also

year, month, day, hour, minute, second, dteq, dtge, dtgt, dtne, dtle

Examples

>>> d = cf.dt(2002, 6, 16)
>>> d == cf.dtlt(1990, 1, 1)
True
>>> d == cf.dtlt(2002, 6, 16)
True
>>> d == cf.dtlt('2100-1-1')
False
>>> d == cf.dtlt('2001-1-1') & cf.dtlt(2010, 12, 31)
True

The last example is equivalent to:

>>> d == cf.wi(cf.dt(2001, 1, 1), cf.dt('2010-12-31'))
True