cf.TimeDuration.bounds

TimeDuration.bounds(dt, calendar=None, direction=True)[source]

Return a time interval containing a date-time.

The interval spans the time duration and starts and ends at date-times consistent with the time duration’s offset.

See also

cf.dt, cf.Datetime, interval

New in version 1.2.3.

Examples 1: 
>>> t = cf.M()
>>> t.bounds(cf.dt(2000, 1, 1))
(<CF Datetime: 2000-1-1 00:00:00>, <CF Datetime: 2000-2-1 00:00:00>)
Parameters:
dt: date-time-like

The date-time to be contained by the interval. dt may be any date-time-like object, such as cf.Datetime, datetime.datetime, netCDF4.netcdftime.datetime, etc.

Example:

To find bounds around 1999-16-1 in the Gregorian calendar you could use dt=cf.dt(1999, 1, 16) or dt=datetime.datetime(1999, 1, 16) (See cf.dt for details).

calendar: str, optional

Define the CF calendar for the input date-time and output time interval. By default the calendar of the input date-time is used. If calendar is set, then the calendar of the input date-time is overridden.

Example:

To set a calendar without leap years: calendar='noleap'.

direction: bool, optional

If False then the bounds are decreasing. By default the bounds are increasing. Note that t.bounds(dt, direction=False) is equivalent to t.bounds(dt)[::-1].
Returns:

out: (cf.Datetime, cf.Datetime)
Examples 2: 
>>> t = cf.M(1)
>>> t.bounds(cf.dt(2000, 3, 1))
(<CF Datetime: 2000-03-01 00:00:00>, <CF Datetime: 2000-04-01 00:00:00>)

>>> t = cf.M(1, day=15)
>>> t.bounds(cf.dt(2000, 3, 1))
(<CF Datetime: 2000-02-15 00:00:00>, <CF Datetime: 2000-03-15 00:00:00>)

>>> t = cf.M(2, day=15)
>>> t.bounds(cf.dt(2000, 3, 1), direction=False)
(<CF Datetime: 2000-03-15 00:00:00>, <CF Datetime: 2000-01-15 00:00:00>)